Venn Diagrams

A Venn diagram turns set notation into a picture. Once your data is placed in the right regions, reading off a probability becomes a matter of adding a few numbers and dividing by the total.

MYP 5Standard MathsSets and Probability~10 min read

The regions of a Venn diagram

A Venn diagram shows sets as overlapping circles inside a rectangle. The rectangle is the universal set \(U\); each circle is one event. Two overlapping circles split the space into four regions.

Region
One part of a Venn diagram. For two sets \(A\) and \(B\) the four regions are: \(A\) only, \(B\) only, the overlap \(A \cap B\), and outside both (which is \((A \cup B)'\)).

The overlap in the middle holds the elements in both sets, the intersection \(A \cap B\). The area outside both circles but still inside the rectangle holds everything in neither.

Placing the data

The golden rule: fill the overlap first. The "both" number goes in the middle, then you subtract it from each circle's total to find the "only" parts. Filling the outer parts of the circles straight from the totals is the fastest way to double count the overlap.

The totals include the overlap

When a question says "18 play football", that \(18\) usually includes the ones who also play something else. Subtract the overlap before writing the football-only region, or your numbers will not add up to the group size.

Worked example

In a class of 30, 18 play football (F), 12 play basketball (B), and 5 play both. Draw the Venn diagram and find the number who play neither, then \(P(F \cup B)\).

1
Overlap first: \(5\) play both, so \(5\) goes in \(F \cap B\).
2
Football only \(= 18 - 5 = 13\); basketball only \(= 12 - 5 = 7\).
3
Inside the circles: \(13 + 5 + 7 = 25\) pupils play at least one sport.
4
Neither \(= 30 - 25 = 5\) pupils, written outside both circles.
5
Probability of at least one sport: \(P(F \cup B) = \dfrac{25}{30} = \dfrac{5}{6}\).
\(5\) pupils play neither, and \(P(F \cup B) = \dfrac{5}{6}\).

Reading probabilities off it

Once every region holds a number, a probability is just the count in the regions you want divided by the total. The addition rule is visible in the picture: adding \(P(A)\) and \(P(B)\) counts the overlap twice, so you subtract it once.

\[ P(A \cup B) = P(A) + P(B) - P(A \cap B) \]

Checking the worked example against the rule: \(\dfrac{18}{30} + \dfrac{12}{30} - \dfrac{5}{30} = \dfrac{25}{30} = \dfrac{5}{6}\), which matches.

Common questions

Most Venn questions ask for one of these regions. Match the wording to the region and read off the count.

Question asks forRegion to read
Both A and BThe overlap \(A \cap B\)
A or B (at least one)Everything inside the circles, \(A \cup B\)
A but not BThe \(A\) only region
NeitherOutside both circles
Not AEverything outside circle \(A\)

Where this is assessed

Placing counts in the correct regions and computing probabilities is Criterion A (Knowing and understanding). A neat, fully labelled diagram with every region filled is Criterion C (Communicating). Sorting survey or club data into a Venn diagram to answer a real question is Criterion D (Applying in real-life contexts).

Check yourself

Use the class-of-30 diagram (football only \(13\), both \(5\), basketball only \(7\), neither \(5\)) for these.

1. What is the probability a pupil chosen at random plays football only? +

The football-only region holds \(13\) pupils out of \(30\). So \(P(\text{football only}) = \dfrac{13}{30}\), which does not simplify. \(\dfrac{13}{30}\).

2. Find the probability a pupil plays neither sport. +

The region outside both circles holds \(5\) pupils, so \(P(\text{neither}) = \dfrac{5}{30} = \) \(\dfrac{1}{6}\).

3. Of 40 people, 22 like tea, 18 like coffee and 10 like both. How many like neither? +

Overlap \(= 10\). Tea only \(= 22 - 10 = 12\); coffee only \(= 18 - 10 = 8\). At least one \(= 12 + 10 + 8 = 30\). Neither \(= 40 - 30 = \) \(10\).


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