Parallel Lines

Parallel lines run in the same direction and never meet. On a graph that means one thing: they have exactly the same gradient. Match the gradient, fit a new point, and you have the equation of a parallel line.

MYP 4Standard MathsCoordinate GeometryCriteria A · C · D~10 min read

What makes lines parallel

Two lines are parallel when they point in the same direction and so never cross, no matter how far you extend them. Because the gradient is what fixes a line's direction, parallel lines share the same gradient.

\[ m_1 = m_2 \]
Parallel lines
Lines with equal gradients but different \(y\)-intercepts. Equal gradients keep them the same steepness, and different intercepts keep them apart.

Spotting parallel lines

When both equations are in the form \(y = mx + c\), just compare the number in front of \(x\). For example, \(y = 2x + 1\) and \(y = 2x - 7\) are parallel, since both have gradient \(2\). If an equation is not in that form yet, rearrange it first, then compare gradients.

Same gradient, different intercept

If two equations share the gradient and the intercept, they are the same line, not a genuine pair of parallel lines. Parallel lines need matching \(m\) but different \(c\).

Finding a parallel equation

To find a line parallel to a given one through a chosen point: copy the gradient, then substitute the point to find the new intercept \(c\).

Worked example

Worked example

Find the equation of the line parallel to \(y = 3x - 4\) that passes through \((1, 5)\).

1
Parallel means the same gradient, so \(m = 3\). Start from \(y = 3x + c\).
2
Substitute the point \((1, 5)\): \(5 = 3(1) + c\).
3
Solve: \(5 = 3 + c\), so \(c = 2\).
\(y = 3x + 2\)

Check yourself

1. Are \(y = 2x + 1\) and \(y = 2x - 7\) parallel? +

Both have gradient \(2\) and different intercepts, so yes, they are parallel.

2. What gradient does any line parallel to \(y = -5x + 3\) have? +

Parallel lines copy the gradient, so it must be \(\mathbf{-5}\).

3. Find the line parallel to \(y = 4x + 1\) through \((0, -3)\). +

Keep \(m = 4\). The point \((0, -3)\) is the \(y\)-intercept, so \(c = -3\). The equation is \(\mathbf{y = 4x - 3}\).


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