The Unit Circle

Once trigonometry grows past right-angled triangles, the unit circle is the map that keeps track of every angle from 0 all the way round to 360 degrees, and it tells you the sign of sin, cos and tan without any guessing.

MYP 5Extended MathsAdvanced Geometry & TrigonometryCriteria A · C~10 min read

Angles all the way round

The unit circle is simply a circle of radius 1, centred on the origin of a set of axes. You measure angles from the positive \(x\)-axis, turning anticlockwise for a positive angle. As a point travels round the edge, its coordinates are exactly \((\cos\theta,\ \sin\theta)\), and that is the whole idea: cos is the across (horizontal) distance and sin is the up (vertical) distance.

Quadrant
One of the four quarters the axes cut the circle into. The first quadrant runs from \(0^\circ\) to \(90^\circ\), the second from \(90^\circ\) to \(180^\circ\), the third from \(180^\circ\) to \(270^\circ\) and the fourth from \(270^\circ\) to \(360^\circ\).

Because sin and cos are read straight off the coordinates, this picture works for angles well beyond the \(0^\circ\) to \(90^\circ\) you met in right-angled triangles. An angle of \(210^\circ\) lands in the third quadrant, where both coordinates are negative, so both \(\sin 210^\circ\) and \(\cos 210^\circ\) come out negative.

Degrees and radians

Degrees are one way to measure a turn, but the other unit, the radian, is the one that makes later work tidier. A full turn is \(360^\circ\), and that same full turn is \(2\pi\) radians. That single fact converts everything:

\[ 180^\circ = \pi \text{ rad} \qquad\qquad \text{degrees} \times \frac{\pi}{180} = \text{radians} \]

So the common angles convert to \(30^\circ=\tfrac{\pi}{6}\), \(45^\circ=\tfrac{\pi}{4}\), \(60^\circ=\tfrac{\pi}{3}\) and \(90^\circ=\tfrac{\pi}{2}\). To go the other way, multiply the radian value by \(\tfrac{180}{\pi}\).

Keep the pi

When converting to radians, leave the answer as an exact multiple of \(\pi\), such as \(\tfrac{2\pi}{3}\), rather than typing it as a decimal. Exact form is what most mark schemes want.

The CAST sign rule

The quadrant a point sits in decides whether each ratio is positive or negative. The word CAST records this, read anticlockwise starting from the fourth quadrant at the bottom right:

QuadrantAnglesPositive ratios
First (A)\(0^\circ\) to \(90^\circ\)All: sin, cos, tan
Second (S)\(90^\circ\) to \(180^\circ\)Sin only
Third (T)\(180^\circ\) to \(270^\circ\)Tan only
Fourth (C)\(270^\circ\) to \(360^\circ\)Cos only

To find an exact value for any angle, pair CAST with the reference angle: the acute angle to the nearest part of the \(x\)-axis. The reference angle gives the size, and CAST gives the sign.

Worked example

Find the exact value of \(\cos 150^\circ\).

1
\(150^\circ\) is in the second quadrant. By CAST, only sin is positive there, so cos is negative.
2
Reference angle to the \(x\)-axis: \(180^\circ - 150^\circ = 30^\circ\).
3
The exact value \(\cos 30^\circ = \tfrac{\sqrt{3}}{2}\), and we attach the negative sign from step 1.
\(\cos 150^\circ = -\dfrac{\sqrt{3}}{2}\)

Exact values to memorise

These five angles turn up constantly, and you are expected to know their ratios without a calculator. It is worth learning this table until it is automatic:

\(\theta\)\(\sin\theta\)\(\cos\theta\)\(\tan\theta\)
\(0^\circ\)\(0\)\(1\)\(0\)
\(30^\circ\)\(\tfrac{1}{2}\)\(\tfrac{\sqrt{3}}{2}\)\(\tfrac{1}{\sqrt{3}}\)
\(45^\circ\)\(\tfrac{\sqrt{2}}{2}\)\(\tfrac{\sqrt{2}}{2}\)\(1\)
\(60^\circ\)\(\tfrac{\sqrt{3}}{2}\)\(\tfrac{1}{2}\)\(\sqrt{3}\)
\(90^\circ\)\(1\)\(0\)undefined

A couple of patterns make this easier to hold on to. The sin column climbs \(0, \tfrac12, \tfrac{\sqrt2}{2}, \tfrac{\sqrt3}{2}, 1\), and the cos column is just that same list read backwards. Each tangent is simply \(\tan\theta = \dfrac{\sin\theta}{\cos\theta}\), which is why \(\tan 90^\circ\) is undefined: you would be dividing by \(\cos 90^\circ = 0\).

Where this is assessed

The unit circle is pure Criterion A (knowing and applying the sign rule and exact values) and Criterion C (writing answers in exact form with correct notation). A rounded decimal where an exact surd was asked for will drop marks.

Check yourself

1. In which quadrant does \(210^\circ\) lie, and is \(\sin 210^\circ\) positive or negative? +

\(210^\circ\) is between \(180^\circ\) and \(270^\circ\), so it is in the third quadrant. By CAST only tan is positive there, so \(\sin 210^\circ\) is negative.

2. Find the exact value of \(\tan 225^\circ\). +

\(225^\circ\) is in the third quadrant, where tan is positive. The reference angle is \(225^\circ - 180^\circ = 45^\circ\), and \(\tan 45^\circ = 1\). So \(\tan 225^\circ = \mathbf{1}\).

3. Convert \(120^\circ\) to radians, leaving your answer in terms of \(\pi\). +

Multiply by \(\tfrac{\pi}{180}\): \(120 \times \tfrac{\pi}{180} = \tfrac{120\pi}{180} = \mathbf{\tfrac{2\pi}{3}}\).


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